Object-oriented programming · interview question
Why does using super() in a constructor change runtime behavior?
Multiple choiceMediumchapter-2-curatedpremiumoopconstructors
Answer and explanation
Correct answer
C. It calls the parent class's no-argument constructor
Why
The 'super()' call in a constructor invokes the parent class's no-argument constructor, ensuring proper initialization of the parent class part of the object.
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