Core Java · interview question
What happens when this try/catch handles division by zero with the wrong exception type?
Multiple choiceHardchapter-6-curatedpremiumcore-javathrow-throws-and-propagation
try {
int result = 10 / 0;
} catch (IOException e) {
System.out.println("Exception caught");
} finally {
System.out.println("Resource closed");
}Answer and explanation
Correct answer
B. Runtime exception
Why
The code throws an ArithmeticException due to division by zero, which is not caught, leading to a runtime exception. The finally block still executes, closing the resource.
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