Core Java · interview question
Consider this code: 'Scanner scanner = new Scanner(System.in); int value = scanner.nextInt(); scanner.nextLine();'. What problem does adding 'scanner.nextLine()' solve?
Multiple choiceHardchapter-1-curatedpremiumcore-javaconsole-input-and-output
Answer and explanation
Correct answer
D. It clears the newline character left in the buffer.
Why
After calling 'nextInt()', the newline character from pressing 'Enter' remains in the buffer. Calling 'nextLine()' immediately after consumes this leftover newline, preventing potential input issues when reading strings subsequently.
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